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20s^2+12s-5s-3=0
We add all the numbers together, and all the variables
20s^2+7s-3=0
a = 20; b = 7; c = -3;
Δ = b2-4ac
Δ = 72-4·20·(-3)
Δ = 289
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{289}=17$$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-17}{2*20}=\frac{-24}{40} =-3/5 $$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+17}{2*20}=\frac{10}{40} =1/4 $
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